1362. Closest Divisors
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Given an integer num, find the closest two integers in absolute difference whose product equals num + 1 or num + 2.
Return the two integers in any order.
Example 1:
Input: num = 8 Output: [3,3] Explanation: For num + 1 = 9, the closest divisors are 3 & 3, for num + 2 = 10, the closest divisors are 2 & 5, hence 3 & 3 is chosen.
Example 2:
Input: num = 123 Output: [5,25]
Example 3:
Input: num = 999 Output: [40,25]
Constraints:
1 <= num <= 10^9
Hints
Hint 1
Find the divisors of n+1 and n+2.
Hint 2
To find the divisors of a number, you only need to iterate to the square root of that number.